session timeout eval random only during night hours

[Matthew Newton]

On Thu, 2019-03-14 at 16:02 -0400, Alan DeKok wrote:
> On Mar 14, 2019, at 3:35 PM, Krzysztof Drewicz <
> krzysztofdrewicz at gmail.com> wrote:
> > 
> > basically what i have is:
> > 
> > Session-Timeout = 24*60*60 (secons so = one day)
> > 
> > what i whould like to eval this timeout every time user gets ack/ok
> > reply
> > to be (randomly) in hours let's say 0200 - 0600 hours.
> 
>   That's a little unusual, and therefore a bit more difficult.
> 
>   There are a few things going on here.  What do you want to do
> *during* that time?  i.e. what happens if the user logs in between
> 0200-0600?
> 
>   If there's outside of that time, it's a bit simpler.  Just
> calculate how far away 0200 is, and then add 0-(4*3600) random
> seconds.

This may work, if I understood the question correctly:

  update reply {
    &Session-Timeout := "%{expr:((%l / 86400) * 86400) + 93600 + %{rand:14400} - %l}"
  }

Request time (%l) / 86400 * 86400 in integer arithmetic gets midnight
of last night.

"+ 93600" adds on 26 hours (2am tomorrow)

"+ %{rand:14400}" adds on between 0-4 hours (i.e. 2am-6am)

"- %l" takes current time off, to get seconds remaining.

-- 
Matthew