27 Aug
2020
27 Aug
'20
11:02 a.m.
James Wood <james.wood@purplewifi.com>
Thanks Brian and Alan for your advice.
If I just perform the mask transform on the last octet this works but of course it returns the result as an int, so I can't find any built in function to get that back to hex.
This is what I've ended up with; please let me know if you feel there is a better/cleaner way without needing the IF statement
Take only the first digit into %{6}. Then mask with 0xC. Then divide by 16. 0/16 is 0, 64/16 is 4, 128/16 is 8 and 192/16 is 12. So then just one if statement makes 12 into "C" and you can just put that back in with a hard coded 0 after it... no need to convert 0 to "0" or 4 to "4" or 8 to "8", they should stringify on their own.